x^2+0.15x=460

Solution for x^2+0.15x=460 equation:

x^2+0.15x=460

We move all terms to the left:

x^2+0.15x-(460)=0

a = 1; b = 0.15; c = -460;
Δ = b2-4ac
Δ = 0.152-4·1·(-460)
Δ = 1840.0225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.15)-\sqrt{1840.0225}}{2*1}=\frac{-0.15-\sqrt{1840.0225}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.15)+\sqrt{1840.0225}}{2*1}=\frac{-0.15+\sqrt{1840.0225}}{2}
$